# Parallel.For Loops in .NET 4

I was having fun working on the Toughest Developer Puzzle Ever 2 when I came across a problem that asked for the coordinates into a grid of numbers of the upper left corner for a 4x4 sub-grid with a magic sum of 34, meaning all rows, columns, and the 2 diagonals all sum up to 34.  Instead of trying to figure it out manually, I probably did what many programmers would do and wrote a quick and dirty program to accomplish the task for me.

I didn’t try to use any optimized search algorithm or anything, as I knew that the problem space was very small and specific and that computers are really fast.  So I figured I would just write a brute-force iterate through every row and column type of an algorithm (in Big O notation being O(mn) or just O(n2) if the original grid is square), knowing it would return in milliseconds.

I quickly realized that each iteration was not dependent any previous iteration for its calculations, so I decided it might be a good time to try out the new Parallel.For loops in the .NET 4 Framework that would multi-thread the iterations of the loops.  Here’s the implementation I threw together:

```using System;
using System.Linq;

namespace Find34Grid
{
public class Program
{
private static readonly int[][] Grid = new []
{
new [] {16,3,2,13,15,10,3,6,41,15,14,4,12,8,7,1,12},
new [] {5,10,22,8,4,5,16,7,9,7,6,12,5,11,10,8,5},
new [] {9,6,7,12,14,11,2,13,16,3,2,13,15,10,3,6,5},
new [] {41,15,14,4,12,8,7,2,5,10,11,8,4,5,16,9,15},
new [] {16,3,2,13,15,10,3,6,15,10,16,2,3,13,16,2,3},
new [] {5,10,11,8,4,5,16,9,4,5,5,11,10,8,5,11,10},
new [] {9,6,7,12,14,11,2,13,14,11,9,7,6,12,9,7,6},
new [] {41,15,14,4,12,8,7,1,12,8,4,14,15,1,14,15,1},
new [] {9,7,6,12,5,11,10,8,5,11,10,3,6,41,15,14,4},
new [] {4,14,15,1,9,7,6,12,9,7,5,16,9,9,7,6,12},
new [] {12,8,13,13,4,14,15,1,4,14,11,2,13,16,3,2,13}
};

private const int MagicSum = 34;

public static void Main(string[] args)
{
Parallel.For(0, Grid.Length - 3, i =>
{
Parallel.For(0, Grid[i].Length - 3, j =>
{
int[] sums = new []
{
Grid[i].Skip(j).Take(4).Sum(), // Row 1
Grid[i+1].Skip(j).Take(4).Sum(), // Row 2
Grid[i+2].Skip(j).Take(4).Sum(), // Row 3
Grid[i+3].Skip(j).Take(4).Sum(), // Row 4
new [] { Grid[i][j], Grid[i+1][j], Grid[i+2][j], Grid[i+3][j]}.Sum(), // Column 1
new [] { Grid[i][j+1], Grid[i+1][j+1], Grid[i+2][j+1], Grid[i+3][j+1]}.Sum(), // Column 2
new [] { Grid[i][j+2], Grid[i+1][j+2], Grid[i+2][j+2], Grid[i+3][j+2]}.Sum(), // Column 3
new [] { Grid[i][j+3], Grid[i+1][j+3], Grid[i+2][j+3], Grid[i+3][j+3]}.Sum(), // Column 4
new [] { Grid[i][j], Grid[i+1][j+1], Grid[i+2][j+2], Grid[i+3][j+3]}.Sum(), // Diagonal 1
new [] { Grid[i][j+3], Grid[i+1][j+2], Grid[i+2][j+1], Grid[i+3][j]}.Sum() // Diagonal 2
};

if (sums.All(x => x == MagicSum))
{
Console.WriteLine("y (row): {0}\nx (column): {1}", i, j);
}
});
});